📘 How does momentum keep score in a collision?
p = mv, impulse, and conservation—how collisions become bookkeeping instead of mystery.
What you’ll learn
- Defining Linear MomentumIntroduce momentum as a vector quantity and relate it to mass and velocity.Momentum equals mass times velocity and carries direction. Students calculate scalar and vector values for everyday objects. The definition sets the stage for all later conservation laws.
- Newton’s Second Law in Momentum FormDerive F equals dp over dt and connect it to the familiar F equals ma form.The net force equals the time derivative of momentum. When mass is constant the equation reduces to ma. This form reveals why force changes motion quantity.
- Impulse and Momentum ChangeDefine impulse as force integrated over time and equate it to the change in momentum.Impulse equals the area under a force-time graph. The impulse-momentum theorem links contact duration to velocity change. Worked examples include bat-ball and airbag collisions.
- Conservation of MomentumState the conservation principle for isolated systems and identify conditions that preserve it.In the absence of external forces the vector sum of momenta stays constant. Internal forces cancel by Newton’s third law. The law applies in one and two dimensions.
- One-Dimensional CollisionsApply conservation of momentum to solve for final velocities in one dimension.Momentum balance yields one equation with two unknowns. Additional information such as coefficient of restitution closes the system. Students solve elastic and inelastic cases.
- Elastic versus Inelastic CollisionsDistinguish elastic and inelastic collisions by kinetic energy conservation.Elastic collisions conserve both momentum and kinetic energy. Inelastic collisions conserve momentum only. The coefficient of restitution quantifies the degree of elasticity.
- Two-Dimensional CollisionsResolve momentum into x and y components to analyze oblique collisions.Vector momentum conservation supplies two independent equations. Students draw before-and-after vector diagrams. A worked billiard-ball example illustrates the method.
- Center of MassLocate the center of mass for discrete and continuous mass distributions.The center of mass moves as if all external forces act there. Internal forces do not affect its motion. Students calculate positions for rods and composite bodies.
- Variable-Mass SystemsDerive the rocket equation using momentum conservation for changing mass.Thrust equals exhaust speed times mass-loss rate. The rocket equation integrates thrust and gravity. Students compute burnout velocity for a single-stage rocket.
- Momentum and Kinetic EnergyRelate momentum and kinetic energy through the relation p squared over 2m.Kinetic energy equals p squared divided by twice the mass. Elastic collisions exchange both quantities in specific ratios. Students compare energy loss in inelastic cases.
- Real-World ApplicationsApply momentum principles to vehicle safety, sports, and ballistic pendulums.Crumple zones extend collision time and reduce force. Ballistic pendulums convert bullet momentum into block height. Students analyze a football tackle example.
- Problem-Solving Strategies and MisconceptionsIdentify common errors and practice systematic solution steps for momentum problems.Draw system boundaries, list known vectors, and apply conservation before energy checks. Students correct misconceptions about direction and reference frames.
Questions this course answers
A 2000 kg truck travels at 15 m/s east. Which statement correctly describes its momentum?
Momentum equals mass times velocity, so 2000 kg times 15 m/s east yields 30000 kg m/s east; the direction matches the velocity.
A 70 kg cyclist rides at 8 m/s. Roughly how large is the momentum?
Momentum is 70 kg times 8 m/s, which equals 560 kg m/s; the slider exercise helps you internalize that everyday speeds and masses already produce hundreds of kg m/s.
A 1500 kg car traveling at 20 m/s applies brakes that exert a constant 6000 N force. Using the momentum form of Newton's second law, what is the car's speed after 4 s?
The force changes momentum at 6000 kg m/s per second, so after 4 s the momentum drops by 24000 kg m/s. Initial momentum was 30000 kg m/s, leaving 6000 kg m/s and thus 4 m/s.
A rocket expels fuel backward while its mass decreases. In one sentence, explain why the momentum form F = dp/dt is required instead of F = ma to describe its acceleration.
Because mass changes, the full derivative dp/dt contains both m dv/dt and the v dm/dt term arising from fuel leaving the rocket; the simpler ma expression therefore misses part of the momentum balance.
A 0.145 kg baseball is struck and its velocity changes from –35 m/s to +40 m/s. Which value equals the impulse delivered by the bat?
Impulse is defined as the integral of force over time; by the impulse-momentum theorem this quantity equals the change in momentum of the ball regardless of how force varied.
A crash dummy moving at 15 m/s is stopped by an airbag in 0.12 s. Estimate the average force on a 70 kg dummy.
Δp = 70 kg × 15 m/s = 1050 kg·m/s. Dividing by 0.12 s gives an average force of 8750 N—roughly twelve times the dummy’s weight—showing how airbags keep forces survivable.
Grounded in trusted sources
- OpenStax
- MIT OpenCourseWare
- American Physical Society
- OpenStax University Physics Volume 1 — Linear Momentum and Collisions
- MIT OpenCourseWare 8.01 — Classical Mechanics
- American Physical Society — momentum and conservation
Every Wunder lesson is built from real, reputable sources — never invented.
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